(1/2x)^2-3x=7x+4-10x

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Solution for (1/2x)^2-3x=7x+4-10x equation: 



(1/2x)^2-3x=7x+4-10x

We move all terms to the left:

(1/2x)^2-3x-(7x+4-10x)=0



Domain of the equation: 2x)^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2x)^2-3x-(-3x+4)=0

We add all the numbers together, and all the variables

-3x+(+1/2x)^2-(-3x+4)=0

We get rid of parentheses

-3x+(+1/2x)^2+3x-4=0

We multiply all the terms by the denominator


-3x*2x)^2+(+3x*2x)^2-4*2x)^2+1=0

Wy multiply elements

-6x^2+12x^3=0

We do not support expression: x^3

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